Learn the method, keep the original restrictions, and practice with 56 worked solutions.
Algebra tiles illustrate the idea of factors. This conceptual image is not a worked proof.
Multiplying and dividing rational expressions becomes much easier when you see a fraction as a collection of factors. The central skill is deciding what those factors are, which ones can be divided out, and which values of the variables must stay excluded. This guide develops that reasoning before you work through the 56 practice questions on this page.
The lesson is intended for students preparing through a school course described as Pre-IB, Integrated Math 3, or a similar algebra pathway. Those labels depend on the school; “Pre IB | IM 3 | Regular” is not an official IB Diploma mathematics course title. The IB lists Mathematics: analysis and approaches and Mathematics: applications and interpretation, each at standard and higher level. For broader course context, see our guide to IB Diploma mathematics.
You will need fraction arithmetic, exponent rules, and basic polynomial multiplication. If a solution feels mysterious, identify which of those foundations is missing. Being able to explain one cancellation correctly is more useful than crossing out several symbols without knowing why.
What makes an expression rational?
A rational expression is a quotient of two polynomials, with a denominator that is not zero. It might contain one variable, several variables, or no variables at all. The word “rational” describes the ratio structure; it does not promise that every value you obtain will be a rational number. In this lesson, variables represent real numbers unless stated otherwise.
PQ,Q≠0
Think of the fraction bar as a grouping symbol. Everything above it belongs to the numerator, and everything below it belongs to the denominator. This matters when you substitute numbers or enter an expression into a calculator. Writing a slash without brackets can turn a quotient of two polynomials into a completely different calculation.
Factors and terms do different jobs
Terms are separated at the outermost level by addition or subtraction. Factors are multiplied together. In the expression below, the expanded form has two terms, while the factored form shows a product. Both forms represent the same polynomial, but only the second makes its common factor immediately visible.
6x2+18x=6x(x+3)
Cancellation is shorthand for dividing the whole numerator and the whole denominator by the same nonzero factor. It is not a rule for erasing repeated letters. If a numerator contains a sum, a letter appearing in only one term is not necessarily a factor of that whole numerator.
x+7x=1+7x,x≠0
You cannot turn this expression into seven by removing the two occurrences of the variable. For instance, substituting two gives nine halves, not seven. By contrast, when the entire numerator is a product containing the denominator as a factor, dividing that factor out is valid. The visual position of a symbol is less important than the operation connecting it to its neighbors.
Why cancellation preserves a value
Suppose the numerator and denominator both contain the same nonzero factor. Dividing each by that factor does not change their ratio. Equivalently, you can separate out a fraction whose numerator and denominator are identical; that fraction equals one. Multiplying by one leaves the other part unchanged.
F·MF·N=FF·MN=MN,F≠0,N≠0
This explains both halves of the cancellation rule. The shared expression must be a factor so that the separation is legitimate, and it must be nonzero so that its ratio with itself is defined. If either condition fails, drawing a line through matching symbols does not justify the step.
Record restrictions before simplifying
The domain is the collection of inputs for which the original expression is defined. A denominator cannot equal zero, even when its numerator also equals zero. Zero divided by a nonzero number is zero; zero divided by zero is undefined. These are different situations and must not be treated as interchangeable.
Find restrictions by factoring every original denominator and considering when any factor becomes zero. You may factor while doing this first check, but record the restrictions before cancelling. For a product of fractions, every fraction must be defined. A zero numerator in one fraction cannot rescue a zero denominator in another.
x2−9x−3=x+3,x≠3
The shorter formula evaluates to six at three, but the original fraction has no value there. Simplification preserves values at allowed inputs; it does not supply a missing value at an excluded input. When presenting the simplified version as an equivalent expression, carry its original restrictions beside the answer.
This distinction also explains why two formulas can look equivalent on a calculator without defining exactly the same function. A function includes both its rule and its domain. Extending a simplified rule to an extra input creates a new function at that input, even if the graphs otherwise match.
Do not exclude a value merely because it makes a numerator zero. In a multiplication problem, that usually produces an allowed zero result. Division has one additional condition: the expression you divide by must itself be nonzero. We will keep that condition separate so it is not lost when the divisor is inverted.
A repeated denominator factor gives the same excluded input more than once, but your domain list only needs that input once. Factor multiplicity still matters during cancellation and when interpreting a graph. Keep these two records distinct: count factor copies in the algebra, and list distinct forbidden inputs in the domain.
Restrictions can also come from the context of a problem. An algebraic formula might allow a negative input even when that input represents a length and therefore cannot be negative. First find where the expression is mathematically defined; then combine that information with any stated real-world constraints. Do not silently invent a positive-input assumption for a purely algebraic question.
The factoring toolkit you actually need
Most of the work in these questions happens before the multiplication. Scan each polynomial for structure rather than applying the same technique everywhere. Begin with a common factor, then inspect what remains. A correct first factorization may still be incomplete, especially when powers or special products are involved.
Monomials, exponents, and the greatest common factor
A monomial is a single term, such as a coefficient multiplied by powers of variables. When multiplying matching bases, add their exponents. When dividing matching nonzero bases, subtract exponents. Keep different variables separate, and simplify the numerical coefficient independently so that arithmetic does not obscure the variable calculation.
x6x2=x4,x2x6=1x4,x≠0
If the powers match exactly, the quotient is one, not zero. If every factor in a numerator cancels, write one in the numerator. An empty numerator is not mathematical notation and can make a correct cancellation look like a zero result.
For a polynomial, find the greatest common numerical factor and the lowest power of each variable shared by every term. Pull that product outside brackets. For example, the common factor in the following polynomial reveals a difference of squares that still needs attention.
10x3−40x=10x(x2−4)=10x(x−2)(x+2)
Multiplying your factors back together is a quick local check. If the middle expression expands correctly but the last one does not, you have isolated the error to the second factorization rather than having to redo the whole problem.
Trinomials and repeated factors
For a quadratic whose leading coefficient is one, look for two numbers whose product is the constant term and whose sum is the coefficient of the linear term. Check both conditions; matching the constant alone is insufficient. Opposite signs are required when the constant is negative.
x2+x−12=(x+4)(x−3)
When the leading coefficient is not one, splitting the middle term can expose grouping. In the next example, the split coefficients multiply to the product of the leading and constant coefficients, while adding to the original middle coefficient. The repeated bracket then becomes a common factor.
6x2+x−2=6x2+4x−3x−2=(3x+2)(2x−1)
A perfect-square trinomial contributes the same factor twice. If the numerator contains two copies and the denominator only one, exactly one copy remains upstairs. Write the repeated factor twice while learning; the extra space can prevent accidental over-cancellation.
x2−10x+25=(x−5)2=(x−5)(x−5)
Differences of squares and sums or differences of cubes
A difference of squares has two square terms joined by subtraction. Recognize the expressions being squared, not just their coefficients. With several variables, the same identity applies to entire monomials. A sum of squares does not use this real linear-factor pattern.
A2−B2=(A−B)(A+B),9u2−16v2=(3u−4v)(3u+4v)
Cubes use a different pattern. The first factor keeps the sign from the original expression. In the quadratic factor, the middle sign is opposite and the final term is positive. Learning the whole identity is safer than guessing from a vaguely familiar bracket.
A3+B3=(A+B)(A2−AB+B2)
A3−B3=(A−B)(A2+AB+B2)
Here the letters stand for complete expressions. If the first cube is eight times a variable cubed, its cube root is twice that variable. Every part of the quadratic factor must use that same cube root. Check a doubtful identity by expansion before using it to cancel.
“Factor completely” always depends on the number system being used. A quadratic may have no rational linear factors but still have real roots. Conversely, a positive quadratic may never be zero for real inputs. Do not invent integer factors just because a worksheet usually contains factorable examples.
Multiplying rational expressions without losing structure
Multiply numerators together and denominators together, just as with numerical fractions. You do not need a common denominator. Factoring first lets you divide out common factors before expanding anything, keeping the intermediate expressions smaller and making restrictions easier to trace.
AB·CD=ACBD,B≠0,D≠0
A factor from either numerator may cancel with a matching factor from either denominator because the combined numerator and denominator are products. This is sometimes called cross-cancellation. The “cross” is only a convenient position on the page; the justification is ordinary fraction simplification, not cross-multiplication.
Example: a product of monomials
14a3b15c2·25bc321a=10a2b2c9,a≠0,c≠0
The numerical part reduces to ten ninths. Across the numerator there are three factors of the first variable, while the denominator contains one, leaving two. The second variable occurs once in each numerator, so its powers combine. The third variable has one more factor upstairs than downstairs.
Notice the domain: the first and third variables cannot be zero because they occur in original denominators. The second variable may be zero. In that case both fractions are defined and their product is zero. Requiring every visible variable to be nonzero would impose an unnecessary restriction.
Example: several polynomial factors cancel
x2+x−12x2−25·x2−10x+25x2−2x−3
The denominators exclude positive five, negative five, three, and negative one. After recording those values, factor all four polynomials. Keep the repeated factor in the second numerator visible so that cancelling one copy does not erase both.
One copy of the factor involving three and one copy of the factor involving five divide out. The resulting answer remains restricted at all four original excluded values. In particular, the final numerator vanishes at five, but that does not make five a valid input to the original product.
Leaving the result factored makes it easy to see that no complete factor appears on both sides of the fraction bar. Expanding the answer is optional unless the instructions ask for it. An expanded answer is not automatically simpler, and it can hide the structure you worked to reveal.
Division adds a nonzero-divisor condition
To divide by a nonzero fraction, multiply by its reciprocal. Reverse only the fraction immediately being used as the divisor, and change the operation to multiplication. Inverting both fractions or leaving the division sign unchanged produces a different expression.
AB÷CD=AB·DC,B≠0,D≠0,C≠0
There are three conditions here. The first fraction must be defined. The second fraction must be defined. The second fraction must also not equal zero. Consequently, its numerator contributes restrictions as well as its denominator. The numerator of the first fraction does not create this extra condition.
A reliable habit is to label the original divisor before changing anything. Write “defined and nonzero” beside it, then inspect both its numerator and denominator. This prevents the original divisor's denominator from being forgotten after it moves to the top of the reciprocal.
Example: a cancellation that hides two exclusions
x2−16x2+x−6÷x−4x+3
The first denominator excludes two and negative three. The divisor's denominator also excludes negative three, so that condition is already on the list. Its numerator excludes four because dividing by a zero expression is not allowed. Now convert the operation and factor.
(x−4)(x+4)(x+3)(x−2)·x+3x−4=x+4x−2,x≠−3,2,4
The final denominator displays only one of the three restrictions. This is why finding the domain from the final line alone gives an incomplete answer. At negative four, however, the original first fraction is zero and the divisor is defined and nonzero. That input is allowed and the quotient is zero.
To test your understanding, compare the division example with the same two fractions multiplied. Multiplication would not exclude four: both original denominators are nonzero there, and the product is zero. Division does exclude four because its second fraction is then zero. The individual fraction formulas did not change, but the operation changed which inputs were valid.
Whole polynomials and chains of operations
If an expression without a fraction bar appears in a division problem, regard it as a fraction over one. There is no need to invent a denominator involving its variable. The reciprocal of a nonzero polynomial is one divided by that polynomial, which explains why its zeros become restrictions when it is the divisor.
For a chain containing multiplication and division without additional grouping, work from left to right, or rewrite each division carefully as multiplication by the appropriate reciprocal. Brackets take priority. Dividing by a product is different from dividing by its first factor and then multiplying by its second. Copying the original grouping accurately is part of the mathematics.
Multivariable restrictions describe relationships
With two or more variables, an excluded input may be a relationship between them rather than a single forbidden number. A denominator factor equal to the difference of two variables excludes equal values. It does not require both variables to be nonzero separately. Always set the complete factor equal to zero to find the actual condition.
u2−4v2u2+uv−2v2÷u−2vu−v
The first denominator factors into a product whose factors vanish when the first variable equals negative twice the second, or when they are equal. The divisor adds a restriction when the first variable equals twice the second. Factoring and taking the reciprocal then gives a particularly short result.
(u−2v)(u+2v)(u+2v)(u−v)·u−vu−2v=1
u≠−2v,u≠v,u≠2v
The answer is one only for pairs satisfying all three conditions. For example, setting the first variable to zero and the second to one is allowed. Setting both to zero is excluded. A constant simplified answer can therefore represent a function with many missing input pairs.
Be especially careful with quadratic factors involving several variables. Over the real numbers, a sum of two squares is zero only when both variables are zero. A restriction such as that sum being nonzero excludes the origin, rather than excluding either coordinate axis. Keeping the complete polynomial condition is acceptable when it communicates the domain more clearly than a long verbal description.
Compact worked-example reference
Use this table to compare the operation, the reduced form, and the information that must survive simplification. The restrictions belong to the original expression in each row. They are not optional notes inferred from the shorter answer.
Three patterns to recognize after factoring
Original expression
Simplified result
Restrictions
z2−36z+6
z−6
z≠−6
t3+27t2−9·t−3t2−3t+9
1
t≠−3,3
k2−25k−2÷(k+5)
k−5k−2
k≠2,−5
In the middle row, the cubic is a sum of cubes. Its linear factor and quadratic factor cancel against the other denominator factors after multiplication. The quadratic denominator is always positive for real inputs: completing its square gives a square plus twenty-seven quarters. Therefore, only the two roots of the difference-of-squares denominator are excluded.
The last row illustrates the distinction between a whole expression and a fraction. The divisor has denominator one, but it can still equal zero. Excluding that zero before taking its reciprocal prevents the missing restriction from disappearing with the common factor.
Catch common mistakes by explaining the operation
When an answer is wrong, simply repeating the calculation faster is unlikely to help. Identify the first line that changes the meaning of the expression. A factoring error, an illegal cancellation, and a missing domain restriction need different repairs.
If you cancelled across addition, reconstruct the whole numerator as a product or leave it unchanged. If you lost a repeated factor, count its copies above and below the fraction bar. If your answer differs only by a sign, inspect factors written in reversed order.
5−x=−(x−5),5−xx−5=−1(x≠5)
Reversed factors are opposites, not identical factors. Pulling out negative one makes the relationship explicit. With two reversed factors, the two negative signs may multiply to positive one; with only one, the negative sign remains. Do not decide the sign by the visual direction of cancellation marks.
Another common mistake is using a common denominator unnecessarily. That technique belongs to addition and subtraction of fractions. Multiplication already combines the denominators as a product. Introducing extra factors usually makes the problem longer and increases the opportunity for cancellation errors.
Finally, keep simplification separate from solving an equation. An expression asks for an equivalent form. An equation asks for inputs that make two sides equal. Setting a numerator equal to zero when no equation has been given answers a question the original problem did not ask.
Why cancellation can leave a hole in a graph
Domain restrictions have a visible interpretation when a rational expression defines a function. Consider this example, whose original denominator excludes negative one and two. One denominator factor cancels completely, while the other remains.
f(x)=x2−1x2−x−2=x−1x−2=1+1x−2,x≠−1,2
At negative one, the simplified formula has the finite value two thirds, but the original function is undefined. Its graph has a hole at the point shown below. At two, the remaining denominator approaches zero while the numerator does not, producing a vertical asymptote. The horizontal asymptote is the line at height one.
The original function has a hole at (−1,23), a vertical asymptote at x=2, and a horizontal asymptote at y=1. The curve is plotted directly from its formula; the open circle preserves the cancelled-factor restriction.
A cancelled factor does not automatically mean a hole if another copy of the same factor remains in the denominator. For example, cancelling one copy from a squared denominator can still leave a vertical asymptote at that input. Classify the excluded value using the fully reduced expression, while retaining the original domain.
You can explore the example with the Sly Academy graphing calculator. Enter numerator and denominator in separate brackets. A plotted curve may appear continuous across a missing point because a single point is smaller than the display resolution or because software simplifies the expression internally. Use your domain calculation to identify the hole rather than treating an unbroken-looking curve as proof that it is absent.
Check answers numerically, then justify them algebraically
Substitution is a useful error detector. Choose a small allowed input, evaluate the original expression exactly if possible, and compare it with the proposed answer. For a multivariable expression, choose a whole input pair or triple that satisfies every restriction. Avoid values that make several numerator factors vanish, because accidental zeros can conceal an incorrect simplification.
Use more than one kind of input when checking: a positive value, a negative value, and sometimes a simple fraction. Negative inputs are particularly helpful for catching reversed-factor sign errors. Never use an excluded input as an ordinary equality test; the original expression has no value there to compare.
Agreement at a few inputs is evidence, not proof of an identity. Two different polynomials can agree at selected inputs and disagree elsewhere. For example, adding a product that vanishes at all your test inputs changes a formula without changing those particular test results. A finite numerical check cannot establish an unrestricted identity without further mathematical conditions.
Your proof is the chain of valid algebraic transformations: correct factorization, reciprocal conversion where appropriate, cancellation of nonzero common factors, and preserved restrictions. If a calculator disagrees, inspect entry brackets and exact fractions before assuming either your algebra or the device must be wrong.
An exact check of the polynomial product
Return to the earlier multiplication example and use zero, which is not on its restriction list. The first fraction becomes twelve twenty-fifths and the second becomes negative twenty-five thirds. Their product is negative four. The simplified expression also gives negative four, so this check finds no disagreement at that input.
Now check the exclusions separately. Positive five is still forbidden even though the simplified formula has a zero numerator there. These are two different verification tasks: evaluating an allowed input tests the value, while reviewing original denominators tests the domain. Doing both is more informative than making many substitutions while ignoring the restrictions.
A practical routine for the 56 questions
The practice set moves from multiplication in questions 1–28 to division in questions 29–56. Start by reading the operation rather than recognizing a familiar-looking polynomial and immediately cancelling. Similar expressions can have different domains when multiplication changes to division.
Work in small groups that share a skill. Begin with monomials to establish coefficient and exponent accuracy. Then practice common factors and quadratics before tackling cubes and multivariable expressions. For a mixed question, name the technique needed for each polynomial before performing the full calculation.
Keep three parts in every written solution: the restrictions, a factored line showing the operation, and the reduced answer. Reveal a worked solution only after you have attempted those parts. If you get stuck, compare the first factorization instead of reading straight through to the final answer.
When reviewing an error, write a short explanation of its cause in ordinary language. “Forgot the divisor can be zero” gives you a specific check for the next division question. “Careless mistake” does not identify anything you can change. Redo the question without the solution visible, then try a different question using the same idea.
Finish a session by explaining one example aloud or in a few sentences. State why the cancellation was legal and why an excluded value remains excluded. You are ready to move on when you can choose the method and defend the domain, rather than merely reproduce the appearance of a worked solution.
Frequently asked questions
Do I need a common denominator to multiply rational expressions?
No. Multiply the numerators and multiply the denominators. Factoring first often reveals common factors that can be divided out before expansion. A common denominator is needed when combining fractions by addition or subtraction, so first check which operation the question actually gives.
Can I cancel the same variable wherever it appears?
No. You can divide out a common nonzero factor of the entire numerator and denominator. A variable inside only one term of a sum is not automatically such a factor. Rewrite the relevant polynomial as a product and check that the proposed cancellation applies to the whole fraction.
Why keep an excluded value after its factor cancels?
Because the original expression remains undefined at that input. The simplified formula represents the same values only on the original domain. Keeping the restriction distinguishes an equivalent representation from a new function that has been extended to include additional inputs.
What extra restriction appears in division?
The divisor must be nonzero as well as defined. Check its numerator for zeros and its denominator for undefined inputs before taking the reciprocal. Also retain restrictions from the first expression. A zero numerator in the first expression is allowed when all the other conditions hold.
Must the final answer be expanded?
Usually a fully reduced factored form is appropriate unless the question specifies another form. It displays the factors clearly and makes further cancellation easy to check. Reduce numerical coefficients, account for signs, and make sure no common nonconstant factor remains above and below the fraction bar.
Does this lesson belong to an official IB mathematics course?
This page uses a school-style Pre-IB or Integrated Math 3 preparation label, not an official IB Diploma subject title. The algebra is useful preparation for later mathematical work, but your school's course outline determines its placement. Consult the official IB mathematics information and your teacher when selecting a Diploma course or level.
Multiplying and dividing rational expressions: practice
Try each of the 56 questions, then open its worked solution. Use Tab to reach a solution control and Enter or Space to open or close it.
Variables are real. Keep the restrictions from the original expression, even after factors cancel. For division, the divisor must also be nonzero. Longer expressions scroll sideways; focus an expression and use the arrow keys if needed.
Multiplication problems (1–28)
Question 1
5y23·9x10y
Show solutionHide solution
Original-domain restrictions
The original denominators must be nonzero.
y≠0
Factor the expressions
No further polynomial factoring is needed. Simplify the numerical coefficients and powers in the next steps.
Multiply the factored expressions
Combine the numerators and denominators as products, keeping every factor.
5y23·9x10y
Cancel common factors and simplify
Divide out equal factors from the numerator and denominator, then simplify the remaining coefficient and powers.
45xy230y=(15y)·(3xy)(15y)·(2)=3xy2
Final answer
3xy2
All original restrictions still apply.
Question 2
2x3y3z4·6xz510y5
Show solutionHide solution
Original-domain restrictions
The original denominators must be nonzero.
y≠0,z≠0
Factor the expressions
No further polynomial factoring is needed. Simplify the numerical coefficients and powers in the next steps.
Multiply the factored expressions
Combine the numerators and denominators as products, keeping every factor.
2x3y3z4·6xz510y5
Cancel common factors and simplify
Divide out equal factors from the numerator and denominator, then simplify the remaining coefficient and powers.
12x4yz530y5z4=(6yz4)·(2x4z)(6yz4)·(5y4)=2x4z5y4
Final answer
2x4z5y4
All original restrictions still apply.
Question 3
9y28·32x27y
Show solutionHide solution
Original-domain restrictions
The original denominators must be nonzero.
y≠0
Factor the expressions
No further polynomial factoring is needed. Simplify the numerical coefficients and powers in the next steps.
Multiply the factored expressions
Combine the numerators and denominators as products, keeping every factor.
9y28·32x27y
Cancel common factors and simplify
Divide out equal factors from the numerator and denominator, then simplify the remaining coefficient and powers.
288xy2216y=(72y)·(4xy)(72y)·(3)=4xy3
Final answer
4xy3
All original restrictions still apply.
Question 4
2x2y3z3·12xz46y3
Show solutionHide solution
Original-domain restrictions
The original denominators must be nonzero.
y≠0,z≠0
Factor the expressions
No further polynomial factoring is needed. Simplify the numerical coefficients and powers in the next steps.
Multiply the factored expressions
Combine the numerators and denominators as products, keeping every factor.
2x2y3z3·12xz46y3
Cancel common factors and simplify
Divide out equal factors from the numerator and denominator, then simplify the remaining coefficient and powers.
24x3yz418y3z3=(6yz3)·(4x3z)(6yz3)·(3y2)=4x3z3y2
Final answer
4x3z3y2
All original restrictions still apply.
Question 5
3y25·10x15y
Show solutionHide solution
Original-domain restrictions
The original denominators must be nonzero.
y≠0
Factor the expressions
No further polynomial factoring is needed. Simplify the numerical coefficients and powers in the next steps.
Multiply the factored expressions
Combine the numerators and denominators as products, keeping every factor.
3y25·10x15y
Cancel common factors and simplify
Divide out equal factors from the numerator and denominator, then simplify the remaining coefficient and powers.
30xy275y=(15y)·(2xy)(15y)·(5)=2xy5
Final answer
2xy5
All original restrictions still apply.
Question 6
4x2y2z2·6xz320y4
Show solutionHide solution
Original-domain restrictions
The original denominators must be nonzero.
y≠0,z≠0
Factor the expressions
No further polynomial factoring is needed. Simplify the numerical coefficients and powers in the next steps.
Multiply the factored expressions
Combine the numerators and denominators as products, keeping every factor.
4x2y2z2·6xz320y4
Cancel common factors and simplify
Divide out equal factors from the numerator and denominator, then simplify the remaining coefficient and powers.
24x3yz340y4z2=(8yz2)·(3x3z)(8yz2)·(5y3)=3x3z5y3
Final answer
3x3z5y3
All original restrictions still apply.
Question 7
x+43x+4y·9x2−16y22x2+3x−20
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Original-domain restrictions
The original denominators must be nonzero.
x≠−4,x≠52,3x+4y≠0
Factor the expressions
Factor these numerators and denominators before cancelling.
9x2−16y2=(3x−4y)(3x+4y)
2x2+3x−20=(x+4)(2x−5)
Multiply the factored expressions
Combine the numerators and denominators as products, keeping every factor.
x+43x+4y·(3x−4y)(3x+4y)(x+4)(2x−5)
Cancel common factors and simplify
Divide out equal factors from the numerator and denominator, then simplify the remaining coefficient and powers.
These primary references support the standard algebra conventions and official course naming. The worked examples and explanations in this guide are original.