|
VECTOR (From R to the point) |
VECTOR coordinates (from the point 𝑅 (12,7) to each point) |
Rotation of 90° (𝑥,𝑦) →(−𝑦,𝑥) |
Final actual image coordinates |
|
𝑅𝐴̅̅̅̅ |
(0,5) |
(−5,0) |
𝐴′ (7,7) |
|
𝑅𝐵̅̅̅̅ |
(3,5) |
(−5,3) |
𝐵′ (7,10) |
|
𝑅𝐶̅̅̅̅ |
(5,5) |
(−5,5) |
𝐶′ (7,12) |
|
𝑅𝐷̅̅̅̅ |
(7,3) |
(−3,7) |
𝐷′ (9 ,14) |
|
𝑅𝐸̅̅̅̅ |
(7,7) |
(−7,7) |
𝐸′ (5,14) |
|
𝑅𝐹̅̅̅̅ |
(8,6) |
(−6,8) |
𝐹′ (6,15) |
|
𝑅𝐺̅̅̅̅ |
(5,8) |
(−8,5) |
𝐺′ (4,12) |
|
𝑅𝐻̅̅̅̅ |
(2,9) |
(−9,2) |
𝐻′ (3,9) |
2) Reflect the lizard across the line
First, rewrite the equation in the form:
The equation given is:
Multiply both sides by 2:
Rewrite in standard form (as above):
In the equation above (in blue), we have:
To find the
-value of the reflected point of each given point, we use the following equations:
Substituting the values of 𝐴 = 1, 𝐵 = −2, 𝐶 = 32, we get:
We now find the reflected point for each point on the lizard:
Let’s look at the first example: Point 𝐴(12,12). This point has the coordinates 
𝑥 value of the reflected point |
𝑦 value of the reflected point |
So the coordinates of 𝐴 are (12,12) and the coordinates of 𝐴’ are (4,28)
Let’s now perform the same operations on all the other points
Graphs of Inverse Trigonometry Functions
AREAS btw CURVES and VOLUMES of REVOLUTIONS
