1.7 Periodic Trends

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Photoelectron Spectroscopy (PES)

Photoelectron Spectroscopy (PES) is a powerful analytical technique used to explore the energies of electrons in atoms, ions, and molecules. PES allows scientists to gain insights into the electronic configuration of elements, shedding light on the different energy levels where electrons reside. It is essentially based on the energy released by electrons emitted from an atom when it interacts with photons (light).

How Does PES Work?

In PES, a sample is bombarded with photons (light particles) of a known frequency. When these photons hit the atoms, they impart energy to the electrons. If the energy provided by the photon is sufficient, it causes the electrons to be ejected from the atom. This process is very similar to the photoelectric effect.

The ejected electrons leave with a certain kinetic energy, which can be measured. By analyzing the energy difference between the photon and the kinetic energy of the emitted electron, the binding energy of each electron can be determined. The binding energy tells us how strongly the electron was held by the atom and helps us understand the atom’s electronic structure.

The photoelectron spectrum that results from this process can tell us:

  • The different energy levels of the electrons within the atom.

  • The electron configuration of the atom, based on the number of electrons in each orbital.

Let’s break down how to interpret these spectra.

Interpreting a Photoelectron Spectrum

Below, we’ll explore the example of a photoelectron spectrum for carbon. This is similar to what you might encounter in an AP Chemistry exam.

 

Understanding the Axes

The first step to interpreting a PES graph is to understand its axes.

  • X-axis (Binding Energy): The x-axis represents the binding energy, which tells us how much energy is required to remove an electron from an atom. Binding energy is essentially a measure of how tightly an electron is held by the nucleus. The greater the binding energy, the closer the electron is to the nucleus.

    • In a PES, binding energy increases from right to left, which means the electrons that are closest to the nucleus appear on the left.

  • Y-axis (Number of Electrons): The y-axis indicates the relative number of electrons in a given energy level. Each peak represents an energy level or orbital, and its height indicates how many electrons are in that level.

Peaks in a Photoelectron Spectrum

In the example PES spectrum of carbon, let’s analyze what each peak means:

  1. First Peak (1s Orbital): The peak closest to the left has the highest binding energy, indicating that these electrons are closest to the nucleus. This is the 1s orbital, and in the case of carbon, it contains 2 electrons.

  2. Second Peak (2s Orbital): Moving to the right, we find another peak, representing the 2s orbital. Carbon also has 2 electrons in this orbital.

  3. Third Peak (2p Orbital): Finally, the next peak corresponds to the 2p orbital. In carbon, the 2p orbital contains 2 electrons.

Therefore, the electronic configuration of carbon based on its PES is 1s² 2s² 2p². This configuration matches the known configuration of carbon and allows us to understand the number and arrangement of electrons in its orbitals.

Big Ideas in Photoelectron Spectroscopy

When interpreting a PES:

  • The position of each peak indicates how much energy is required to remove an electron from that sublevel, which directly relates to the electron’s distance from the nucleus.

  • The height of each peak shows the number of electrons in that sublevel.

Example Questions to Practice

Let’s go through some example questions that might appear on an AP Chemistry exam:

  1. Refer to the photoelectron spectrum of neon. Which of the following statements best accounts for peak A being to the left of peaks B and C?

    • a. The electron configuration of neon is 1s² 2s² 2p⁶.

    • b. Neon has 8 electrons located in its valence shell.

    • c. Core electrons of an atom experience a much greater attraction to the nucleus than valence electrons.

    • d. Peaks B and C show the first ionization energies in neon, whereas peak A shows the second ionization energy.

    Answer: The correct answer is c. Core electrons are closer to the nucleus, which means they have a higher binding energy, hence why peak A is positioned to the left.

  2. Which peak shows electrons closest to the nucleus?

    • Options: A, B, C, D

    Answer: Peak A represents the electrons closest to the nucleus. Electrons that are closer have higher binding energy and are represented by peaks on the left side of the graph.

AP Practice Question – 2019 Exam Example

This is a sample question adapted from the 2019 AP Chemistry exam:

Part (a) of the question asks you to write the electron configuration and identify the element based on its photoelectron spectrum.

  • Start by identifying each peak in the graph, starting from the left. Assign each peak to its respective orbital.

  • Write the electron configuration for the element, considering the number of electrons represented by each peak.

If you determine that the binding energy is highest on the left, you start with the 1s orbital. As you move to the right, assign each peak to subsequent orbitals, such as 2s, 2p, etc. The electron configuration you derive from this analysis can be used to identify the element on the periodic table.

Summary

Photoelectron Spectroscopy is an insightful tool for understanding the electron configuration of elements. It allows us to visualize the binding energy of electrons and identify where they are located within an atom. By understanding the basic principles—such as interpreting the axes of a graph and analyzing peaks—you will be well-prepared for any related question on the AP Chemistry exam. The key concepts include the relationship between binding energy and proximity to the nucleus, as well as the number of electrons in a given energy level. Keep practicing, and soon you’ll be comfortable with this important analytical technique!

5 Periodic Trends to Know for AP Chemistry

The periodic table is a treasure trove of patterns that help us understand the behavior and properties of elements. For the AP Chemistry exam, it’s crucial not only to know these trends but also to understand why they happen. Here are five key periodic trends you should master, along with explanations rooted in nuclear charge and electron configuration.

1. Atomic Radius

Definition: The atomic radius is the distance from an atom’s nucleus to its outermost electrons.

  • Across a Period (Left to Right): Atomic radii decrease. This happens because as you move across a period, the atomic number increases, meaning there are more protons in the nucleus. The increased positive charge pulls the electrons closer, reducing the atomic size.

  • Down a Group (Top to Bottom): Atomic radii increase. As you move down a group, the number of occupied electron shells increases. More shells mean a greater distance between the nucleus and the valence electrons, making the atomic radius larger.

 

2. Ionic Radius

Definition: The ionic radius is the distance from the nucleus to the outermost electrons in an ion.

  • Positive Ions (Cations): Smaller than their neutral atoms. Metals lose electrons to form cations, resulting in fewer electrons, less electron-electron repulsion, and a smaller radius.

  • Negative Ions (Anions): Larger than their neutral atoms. Nonmetals gain electrons to form anions, which increases electron-electron repulsion and makes the ion larger.

 

3. Electronegativity

Definition: Electronegativity is a measure of how strongly an atom’s nucleus attracts electrons from another atom in a bond.

  • Across a Period: Increases. Elements on the right of the periodic table (like halogens) have more protons, giving their nuclei a stronger positive charge. This makes them more effective at attracting electrons.

  • Down a Group: Decreases. As atomic size increases down a group, the nucleus is farther away from the bonding electrons, reducing its ability to attract them.

Tip: Fluorine is the most electronegative element, with a value of 4.0. Compare other elements based on their proximity to fluorine.

4. Ionization Energy

Definition: Ionization energy is the energy required to remove an electron from an atom.

  • Across a Period: Increases. Smaller atomic size means the nucleus is more strongly attracting the electrons, making it harder to remove them.

  • Down a Group: Decreases. The increased number of electron shells results in the valence electrons being farther from the nucleus and less tightly held, making them easier to remove.

Note: The second ionization energy is always higher than the first, as removing additional electrons from an already positively charged ion requires more energy.

Exceptions: Group 15 elements have higher first ionization energies than Group 16 due to electron pairing effects. For example, sulfur (S) has a lower first ionization energy than phosphorus (P) because the paired electrons in the sulfur atom’s orbital experience more electron-electron repulsion, making them easier to remove.

  • Quantum Tunneling: Electrons in s-orbitals (like those in beryllium) are closer to the nucleus compared to p-orbitals (like those in boron). This makes the removal of a p-electron easier than an s-electron, leading to trends like Be > B for ionization energy.

5. Electron Affinity

Definition: Electron affinity refers to the energy change that occurs when an electron is added to a neutral atom, indicating how much an atom wants an extra electron.

  • Across a Period: Increases (more negative). As you move right across a period, atoms become more eager to gain an electron to achieve a full valence shell.

  • Down a Group: Decreases (less negative). Larger atoms are less effective at attracting an additional electron due to the increased distance between the nucleus and the outer shell.

    Valence Electrons

    Using the ionization energies given below, determine the number of valence electrons this element has:

    • I₁ = 500

    • I₂ = 1500

    • I₃ = 7000

    • I₄ = 9000

    When you are given this type of question, just look for the significant jump in ionization energies. This large jump indicates the transition from valence electrons to core electrons, which are much harder to remove because they are closer to the nucleus.

    In this example, there is a significant jump between I₂ and I₃. Therefore, this element has 2 valence electrons.

    Electron Affinity

    Electron affinity is the energy change when an electron is added to an atom in the gaseous state.

    • Across a Period: Electron affinity becomes more negative.

    • Down a Group: Electron affinity becomes more positive.

    The more negative the energy, the more energy is released! Electron affinity is typically negative because an atom releases energy when it gains an electron. However, how negative it is depends on periodic trends. You can explain this trend by considering electronegativity.

    While you might expect fluorine to have the highest magnitude of electron affinity, chlorine actually does! Fluorine is a very small atom, and the electrons are so close together that they repel each other, which requires additional energy.

     


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